Our last articles about combining supercharger performance with turbocharger top end seems to have found some online appreciation. So, I’ve decided to write up a step by step on how to do the math for twin-charging your own car.

I’m going to start with a typical compact car engine, such as the Toyota Celica 2.2 liter 5sfe engine. The engine makes 135 hp at 5200 RPMs with a 6200 RPM redline.

For starters, every horsepower requires about 1.5 CFM of air (depending on the air density).

So 135 naturally aspirated hp requires a flow of 202 CFM at pressure ratio of 1.

The pressure ratio is the ratio of turbocharger or supercharger boost pressure divided by atmospheric pressure. Each 1 atmosphere is equal to 14.7psi of pressure… thus:

PR = (14.7 + Boost pressure)/14.7

So for a normally aspirated car: PR = (14.7 + 0) / 14.7 = 1.

Supercharger calculations:

Using 14psi as our target boost (and the maximum safe boost we’d want to extract out of a roots style supercharger) we get the following pressure ratio:

PR = (14.7+14)/14.7 = 1.95

New expected horsepower level: old HP * pressure ratio

New HP = 135 * 1.95 = 263 HP

New CFM = 227 * 1.5 = 395 CFM.

So now, we have our supercharger flow requirements, we need a supercharger able flow 395 CFM at a pressure ration of 1.95 (or 10psi).

Going through different Eaton supercharger maps I had available I find one available option:

1-      The third generation M62 or the fourth generation MP62 are capable of producing 395 CFM @ 1.95 PR @ 13,000 RPMs.

Criterion

Eaton M62

CFM @ PR

395 @ 1.95

RPM

13,000

Horsepower required to drive the supercharger at peak RPM

35 hp @ 13,000 RPM

delt T (temperature increase at supercharger outlet)

160 * F @ 11,000 RPM

 

My final expected hp is going to be less than the original estimate263 for two reasons:

1-      The supercharger requires 35 hp to drive it at 13,000 rpms.

2-      The outlet temperature (if not managed through a proper intercooler) is going to be 88*C higher than the inlet temperature, and with every 13*C by rule of thumb costing us 1 hp of power, then 88*C would equate to a power loss of 7 hp.

Our final supercharged power figure (with no intercooler and no other bolt-ons) is

Final hp = (original hp * pressure ratio) – supercharger drive power – (delta T (Centigrade) / 13)

Final hp = 263 – 35 – 7 = 221 HP